## 6.7.4 Angles and Tangents of Circles, PT3 Focus Practice

Question 9: In figure above, ABC is a tangent to the circle centre O, at point B. The value of x is Solution: ∠OBC = 90o ∠BOD = 2 × 50o = 100o In quadrilateral BODC, xo = 360o – ∠BOD – ∠OBC – 120o = 360o – 100o – 90o – 120o = 50 Question 10: … Read more