6.6.2 Angles and Tangents of Circles, PT3 Practice


6.6.2 Angles and Tangents of Circles, PT3 Practice

Question 4:
Diagram below shows a circle with centre O. POR is a straight line.

Find the value of x and of y.

Solution:
x = 40 × 2 = 80 y = 180 − 80 2 = 50


Question 5:
Diagram below shows a semicircle ABCD with centre O.

It is given that AB = CD.
Find the value of y.

Solution:

yo + 32o + 32o + 90o = 180o
yo = 180o – 154o
yo = 26o
y = 26


Question 6:
In diagram below, ABC and DEF are straight lines.

Find the value of x and of y.

Solution:
x+38=93 x=93−38 x=55 ∠DBG= 38 o  ( GB=GD )     y o =∠DBG ∴y=38

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