## 10.4.2 Gradient of a Straight Line, PT3 Focus Practice

Question 6: Diagram below shows a straight line RS with equation 3y = –px – 12, where p is a constant. It is given that OR: OS = 3 : 2. Find the value of p. Solution: Method 1: Substitute x= –6 and y = 0 into 3y = –px – 12: 3(0) = –p … Read more