6.7.3 Angles and Tangents of Circles, PT3 Focus Practice



Question 7:


In figure above, ABCD is a tangent to the circle CEF at point C. EGC is a straight line. The value of y is
 
Solution:
∠ C E F = ∠ D C F = 70 ∘ ∠ A E G + 70 ∘ + 210 ∘ = 360 ∘ ∠ A E G = 80 ∘ In cyclic quadrilateral A B G E , ∠ A B G + ∠ A E G = 180 ∘ y ∘ + 80 ∘ = 180 ∘ y = 100


Question 8:

In figure above, ABC is a tangent to the circle centre O at B. AED is a straight line.
Find the value of y.

Solution:
∠ABO = 90o
∠BOE = 2 × 40o = 80o
In quadrilateral AEOB,
∠AEO = 360o  – ∠ABO  – ∠BOE – 35o
= 360o  – 90o – 80o – 35o = 155o
yo+ ∠AEO = 180o 
yo+ 155o = 180o
yo = 180o  – 155o
y o = 25

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