10.2.1 Gradient of a Straight Line (Sample Questions)


Example 1:
Given that a straight line passes through points (-3, -7) and (4, 14). What is the gradient of the straight line?

Solution:
Let (x1, y1) = (-3, -7) and (x2, y2) = (4, 14).

Gradient of the straight line 
=y2−y1x2−x1=14−(−7)4−(−3)=217=3



Example 2:
The gradient of the straight line PQ in the diagram above is

Solution:
Let (x1, y1) = (12, 0) and (x2, y2) = (0, 7).

Gradient of the straight line PQ
=y2−y1x2−x1=7−00−12=−712




Example 3:
A straight line with gradient -3 passes through points (-4, 6) and (-1, p). Find the value of p.

Solution:
y2−y1x2−x1=−3p−6−1−(−4)=−3p−63=−3p−6=−9p=−3

Leave a Comment