Question 5 (a):
Diagram 5.1 shows a right-angled triangle.
![](http://pt3matematik.blog.onlinetuition.com.my/wp-content/uploads/sites/11/2019/09/Picture72-300x188.png)
Match cos θ and tan θ to the correct trigonometric ratio.
Answer:
![](http://pt3mathematics.blog.onlinetuition.com.my/wp-content/uploads/sites/6/2019/09/Picture73.png)
Solution:
![](http://pt3mathematics.blog.onlinetuition.com.my/wp-content/uploads/sites/6/2019/09/Picture74.png)
Diagram 5.1 shows a right-angled triangle.
![](http://pt3matematik.blog.onlinetuition.com.my/wp-content/uploads/sites/11/2019/09/Picture72-300x188.png)
Match cos θ and tan θ to the correct trigonometric ratio.
Answer:
![](http://pt3mathematics.blog.onlinetuition.com.my/wp-content/uploads/sites/6/2019/09/Picture73.png)
Solution:
![](http://pt3mathematics.blog.onlinetuition.com.my/wp-content/uploads/sites/6/2019/09/Picture74.png)
Question 5 (b):
Diagram 5.2 shows a trapezium ABCD.
![](http://pt3matematik.blog.onlinetuition.com.my/wp-content/uploads/sites/11/2019/09/Picture67-1.png)
Calculate the area, in cm2, of the shaded region.
Solution:
Diagram 5.2 shows a trapezium ABCD.
![](http://pt3matematik.blog.onlinetuition.com.my/wp-content/uploads/sites/11/2019/09/Picture67-1.png)
Calculate the area, in cm2, of the shaded region.
Solution:
Question 5 (c):
(i) Simplify a-2 ÷ a3
(ii) It is given that 53x + 4 ÷ 53 = 125.
Find the value of x.
Solution:
(i)
a-2 ÷ a3 = a-2-3
= a-5
(ii)
53x + 4 ÷ 53 = 125
53x + 4 – 3 = 53
53x + 1 = 53
3x + 1 = 3
3x = 2
x = ⅔
(i) Simplify a-2 ÷ a3
(ii) It is given that 53x + 4 ÷ 53 = 125.
Find the value of x.
Solution:
(i)
a-2 ÷ a3 = a-2-3
= a-5
(ii)
53x + 4 ÷ 53 = 125
53x + 4 – 3 = 53
53x + 1 = 53
3x + 1 = 3
3x = 2
x = ⅔