Question 4 (a):
Table 4 shows the freezing point of six solvents.

(i) State the solvent which has the highest freezing point.
(ii) Find the difference in freezing points between benzene and chloroform.
(iii) State the number of solvents which freezing points are lower than acetic acid.
Solution:
(i)
Phenol
(ii)
Difference in freezing points between benzene and chloroform
= 5.5 – (–63.5)
= 69 oC
(iii)
Number of solvents which freezing points are lower than acetic acid = 4 (benzene, water, chloroform, ethanol).
Table 4 shows the freezing point of six solvents.

(i) State the solvent which has the highest freezing point.
(ii) Find the difference in freezing points between benzene and chloroform.
(iii) State the number of solvents which freezing points are lower than acetic acid.
Solution:
(i)
Phenol
(ii)
Difference in freezing points between benzene and chloroform
= 5.5 – (–63.5)
= 69 oC
(iii)
Number of solvents which freezing points are lower than acetic acid = 4 (benzene, water, chloroform, ethanol).
Question 4 (b):
Diagram 4 shows two right angled triangles, PRQ and SRT. PRS is a straight line.
Find the length, in cm of ST. Round off the answer to two decimal places.
Solution:
PR2=262−242PR=√262−242PR=√100PR=10ST2=102+162ST=√102+162ST=√356ST=18.87 cm
Diagram 4 shows two right angled triangles, PRQ and SRT. PRS is a straight line.

Solution:
PR2=262−242PR=√262−242PR=√100PR=10ST2=102+162ST=√102+162ST=√356ST=18.87 cm
Question 4 (c):
It is given that 25 of Alex’s money is equal to 14 of Benny’s money.
If Benny has RM100, calculate the total amount of money for both of them.
Solution:
Let’s the money of Alex=y25y=14×100y=14×52×100y=62.50Total amount of their money=RM 100 + RM 62.50= RM 162.50
It is given that 25 of Alex’s money is equal to 14 of Benny’s money.
If Benny has RM100, calculate the total amount of money for both of them.
Solution:
Let’s the money of Alex=y25y=14×100y=14×52×100y=62.50Total amount of their money=RM 100 + RM 62.50= RM 162.50