2.3.3 Standard Form, PT3 Focus Practice


Question 11:
Express 0.0000643.5×106 in standard form.

Solution:
0.0000643.5×106=6.4×1053.5×106=6.4×1050.35×105=(6.40.35)×105=6.05×105

Question 12:
200.7×1011 is written as 2.007×10b in the standard form.State the value of b.

Solution:
200.7×1011=2.007×102×1011                  =2.007×1013                b=13

Question 13:
Find the product of 0.1985 and 0.5.
Round off the answer correct to two significant figures.

Solution:
0.1985 × 0.5
= 0.09925
= 0.10 (two significant figures)

Question 14:
The area of a rectangular public parking area is 7.2 km2 . Its width is 2400 m. The length, in m, of the parking area is

Solution:
Area = Length × WidthLength × 2.400 km = 7.2 km2Length=7.22.4   =3 km   =3000 m   =3×103 m

Question 15:
It is given that 30 solid metal cylinders each with a radius of 70 cm and a height of 300 cm, are melted to make 40 identical solid spheres.
Find the volume, in cm3 , of each solid sphere.

Solution:
Volume of 40 spheres= Volume of 30 cylinders=30×227×702×300=138 600 000 cm3Volume of 1 sphere =138 600 00040=3 465 000 cm3=3.465×106 cm3=3.47×106 cm3

Leave a Comment