2.2.2 Factorisation and Algebraic Fractions, PT3 Practice


Question 5:
(a) Simplify:
(m – 4n)(m + 4n) – m2
(b) Simplify: 3x3yx+y×2x+2y6x3x3yx+y×2x+2y6x  

Solution:
(a)
(m – 4n)(+ 4n) – m2
= m2 + 4mn – 4mn – 4n2m2
= 0
 
(b)
3x3yx+y×2x+2y6x=3(xy)x+y×2(x+y)6x=xyx



Question 6:
(a) Simplify each of the following:
(i)12mn32(ii)x2xyx
(b) Express 12q2p76q  as a single fraction in its simplest form.

Solution:

(a)(i)12mn32=3mn8(a)(ii)x2xyx=x(xy)x=xy

(b)

12q2p76q=1×32q×3(2p7)6q=32p+76q=102p6q=2(5p)36q=5p3q


Question 7:
(a) Factorise 2ae + 3af – 6de – 9df
(b)   Simplify a2b2(a+b)2

Solution:
(a)
2ae + 3af – 6de – 9df = (2+ 3f ) – 3d (2e + 3f)
= (2+ 3f ) (a – 3d)

(b)
a2b2(a+b)2=(a+b)(ab)(a+b)(a+b)=aba+b


Question 8:
(a) Factorise –8c2 – 12ac.
(b)   Simplify ae+ad2be2bda24b2.  

Solution:
(a)
–8c2– 12ac
= –4c (2c + 3a)

(b)
ae+ad2be2bda24b2=a(e+d)2b(e+d)(a+2b)(a2b)=(e+d)(a2b)(a+2b)(a2b)=e+da+2b

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