8.2.2 Basic Measurements, PT3 Practice


Question 6:
The mass of a box containing 6 papayas is 21.32 kg. The mass of the box when it is empty is 1.46 kg.
Calculate the average mass, in g, of a papaya.

Solution:
Mass of 6 papayas
= 21.32 – 1.46
= 19.86 kg

Average mass of a papaya
= 19.86 ÷ 6
= 3.31 kg
= 3.31 × 1000 g
= 3310 g



Question 7:
Louis bought 600 g of cookies. Dennis bought twice the mass of cookies that Jackson bought. They bought 1.35 kg of cookies altogether. Calculate the mass, in g, of cookies bought by Jackson.

Solution:
Let Jackson bought w g of cookies.
600 g + 2 × w + w = 1.35 kg
600 g + 3w = 1.35 kg
600 g + 3w = 1350 g
3w = 1350 g – 600 g
w = 750 g ÷ 3
w = 250 g



Question 8:
If the mass of 4 packets of candies is 2.6 kg, what is the mass of 9 packets of the same candies, in kg?

Solution:
Mass of 4 packets of candies = 2.6 kg Mass of 9 packets of candies= 2.6 4 ×9  =5.85 kg


Question 9:
It is given that 1 4 of fruits is supplied to Juice Stall A and 2 7 to Juice Stall B. The remaining 133.25 kg is sold to a fruit stall.
Calculate the mass of fruits that has been supplied to Fruit Stall B.

Solution:
1 4 + 2 7 = 7 28 + 8 28          = 15 28 Remaining fruits sold to fruit stall =1 15 28 = 13 28 Total mass of fruits = 28 13 ×133.25 =287 kg Mass of fruits supplied to Juice Stall B = 2 7 ×287 =82 kg

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