5.2.1 Ratio, Rates and Proportions (I), PT3 Focus Practice


5.2.1 Ratio, Rates and Proportions (I), PT3 Focus Practice

Question 1:
Given x : y = 4 : 5 and x + y = 180. Find the value of x.

Solution:
Given x:y=4:5 and x+y=180 x x+y = 4 4+5 x 180 = 4 9 x= 4 9 ×180  =80
 

Question 2:
Given x : y = 9 : 5 and xy = 16. Find the value of x + y.

Solution:
Given x:y=9:5 and xy=16 x+y xy = 9+5 95 x+y 16 = 14 4 x+y= 7 2 ×16 =56 x+y=56



Question 3:
Amy, Rizal and Muthu donated to a charity fund in the ratio of 2 : 1 : 3. The total donation from Amy and Muthu was RM360.
Calculate the amount donated by Rizal.

Solution:
Amy : Rizal : Muthu = 2 : 1 : 3
Rizal Amy + Muthu = 1 2+3 Rizal RM360 = 1 5 Rizal= 1 5 ×RM360 =RM72



Question 4:
In the figure, TU: UV : VW = 5 : 7 : 2.
 
If TU = 30 cm, what is the length of TW?

Solution:
Given TU:UV:VW=5:7:2 TU=30cm TU+UV+VW TU = 5+7+2 5 TW 30 = 14 5 TW= 14 5 ×30 =84cm


Question 5:
In diagram below, ABC is a triangle.
The sides of the triangle are in the ratio AB : BC: CA = 4 : 7 : 6.
Find the difference in length, in cm, between AB and CA.

Solution:
AB:BC:CA=4:7:6 BC=35cm AB BC = 4 7 AB 35 = 4 7 AB= 4 7 ×35 =20cm CA 35 = 6 7 CA= 6 7 ×35 =30cm

Difference in length between AB and CA
= 30 – 20
= 10 cm

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