3.2.2 Fractions, PT3 Practice


Question 6:
1 1 2 ÷ 1 4 × 4 5 =

Solution:
1 1 2 ÷ 1 4 × 4 5 = 3 2 × 4 2 1 × 4 5 = 24 5 =4 4 5


Question 7:
4 1 5 ÷1 1 6 ×2 2 9 =

Solution:
4 1 5 ÷1 1 6 ×2 2 9 = 21 3 5 × 6 2 7 × 20 4 9 3 =8


Question 8:
2 3 4 ×1 1 3 ÷7 1 3 =

Solution:
2 3 4 ×1 1 3 ÷7 1 3 = 11 4 × 4 3 ÷ 22 3 = 11 4 × 4 3 × 3 22 2 = 1 2


Question 9:
4 5 6 2 1 3 ÷ 5 9 =

Solution:
4 5 6 2 1 3 ÷ 5 9 =4 5 6 ( 7 3 ÷ 5 9 ) =4 5 6 ( 7 3 × 9 3 5 ) =4 5 6 21 5 =4 5 6 4 1 5 = 25 30 6 30 = 19 30


Question 10:
( 7 9 + 11 15 )÷( 7 8 15 4 1 5 )=

Solution:
( 7 9 + 11 15 )÷( 4 8 15 3 1 5 ) =( 35 45 + 33 45 )÷( 4 8 15 3 3 15 ) = 68 45 ÷1 5 15 = 68 45 ÷1 1 3 = 68 45 ÷ 4 3 = 68 17 45 15 × 3 4 = 17 15 =1 2 15

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